2CH₃OH + 3O₂ → 2CO₂ + 4H₂O

Combustion of methanol — balanced chemical equation, step by step.

Methanol is burned as a racing fuel and is used directly in some fuel cells.

How to balance CH3OH + O2 = CO2 + H2O

A combustion reaction burns a fuel in oxygen (O₂), releasing energy and producing carbon dioxide and water. Balancing means choosing coefficients so that every element has the same number of atoms on both sides of the arrow — the Law of Conservation of Mass. Here is how it's done, step by step.

Step 1 — Write the unbalanced equation

Start with the correct formulas for every reactant and product:

CH3OH + O2 = CO2 + H2O

Step 2 — Count the atoms of each element

With no coefficients yet (everything counted once), the atoms do not match. The ✗ marks show which elements are unbalanced:

Step 3 — Add the smallest whole-number coefficients

Adjust the coefficients in front of each formula until every element balances. The smallest whole-number coefficients are 2 CH₃OH, 3 O₂, 2 CO₂, 4 H₂O, giving:

2CH3OH + 3O2 = 2CO2 + 4H2O

For combustion reactions, balance carbon (C) first, then hydrogen (H), and leave oxygen (O) for last — oxygen appears alone as O₂, so it is easiest to adjust at the end.

Step 4 — Verify the balance

Recount every element. Each one now matches on both sides:

All elements are balanced and the coefficients are the smallest whole numbers, so 2CH3OH + 3O2 = 2CO2 + 4H2O is the correct balanced equation.

Molar masses and mole ratio

The balanced coefficients are also the mole ratio of the reaction. Using standard atomic masses, the molar mass of each substance is:

For this reaction the mole ratio is 2 : 3 : 2 : 4. Combine these molar masses with the ratio in the free stoichiometry calculator to convert between moles, grams, and the number of particles for any reactant or product.

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