BalancerEquations › 2KMnO4 = K2MnO4 + MnO2 + O2

2KMnO4 K2MnO4 + MnO2 + O2

Decomposition of potassium permanganate — balanced chemical equation, step by step.

Balanced equation
2KMnO4 K2MnO4 + MnO2 + O2
Decomposition reaction

Potassium permanganate decomposes on heating, releasing oxygen and forming manganese oxides.

How to balance KMnO4 = K2MnO4 + MnO2 + O2

A decomposition reaction breaks one compound down into two or more simpler substances. Balancing means choosing coefficients so that every element has the same number of atoms on both sides of the arrow — the Law of Conservation of Mass. Here is how it's done, step by step.

Step 1 — Write the unbalanced equation

Start with the correct formulas for every reactant and product:

KMnO4 = K2MnO4 + MnO2 + O2

Step 2 — Count the atoms of each element

With no coefficients yet (everything counted once), the atoms do not match. The ✗ marks show which elements are unbalanced:

ElementReactantsProductsEqual?
K12
Mn12
O48

Step 3 — Add the smallest whole-number coefficients

Adjust the coefficients in front of each formula until every element balances. The smallest whole-number coefficients are 2 KMnO4, 1 K2MnO4, 1 MnO2, 1 O2, giving:

2KMnO4 = K2MnO4 + MnO2 + O2

For a decomposition reaction, balance the element common to the fewest products first, then work outward to the simpler substances.

Step 4 — Verify the balance

Recount every element. Each one now matches on both sides:

ElementReactantsProductsBalanced
K22
Mn22
O88

All elements are balanced and the coefficients are the smallest whole numbers, so 2KMnO4 = K2MnO4 + MnO2 + O2 is the correct balanced equation.

Molar masses and mole ratio

The balanced coefficients are also the mole ratio of the reaction. Using standard atomic masses, the molar mass of each substance is:

SubstanceRoleMolar mass (g/mol)Moles
KMnO4reactant158.032
K2MnO4product197.131
MnO2product86.941
O2product321

For this reaction the mole ratio is 2 : 1 : 1 : 1. Combine these molar masses with the ratio in the free stoichiometry calculator to convert between moles, grams, and the number of particles for any reactant or product.

Try another equation

Use the free balancer to solve any reaction instantly with step-by-step explanations and a stoichiometry calculator.

Open the balancer →

Related decomposition reactions