AgNO3 + NaCl → AgCl + NaNO3
Silver nitrate and sodium chloride — balanced chemical equation, step by step.
This forms a white silver chloride precipitate, the standard chemical test for chloride ions.
How to balance AgNO3 + NaCl = AgCl + NaNO3
In a double-replacement reaction, the ions of two compounds swap partners — often forming a precipitate. Balancing means choosing coefficients so that every element has the same number of atoms on both sides of the arrow — the Law of Conservation of Mass. Here is how it's done, step by step.
Step 1 — Write the unbalanced equation
Start with the correct formulas for every reactant and product:
AgNO3 + NaCl = AgCl + NaNO3
Step 2 — Count the atoms of each element
Counting the atoms on each side, every element already matches — so each coefficient is 1:
| Element | Reactants | Products | Equal? |
|---|---|---|---|
| Ag | 1 | 1 | ✓ |
| N | 1 | 1 | ✓ |
| O | 3 | 3 | ✓ |
| Na | 1 | 1 | ✓ |
| Cl | 1 | 1 | ✓ |
Step 3 — Add the smallest whole-number coefficients
Adjust the coefficients in front of each formula until every element balances. The smallest whole-number coefficients are 1 AgNO3, 1 NaCl, 1 AgCl, 1 NaNO3, giving:
AgNO3 + NaCl = AgCl + NaNO3
For a double-replacement reaction, treat each polyatomic ion (such as NO₃⁻ or SO₄²⁻) as a single unit and balance those groups before the individual atoms.
Step 4 — Verify the balance
Recount every element. Each one now matches on both sides:
| Element | Reactants | Products | Balanced |
|---|---|---|---|
| Ag | 1 | 1 | ✓ |
| N | 1 | 1 | ✓ |
| O | 3 | 3 | ✓ |
| Na | 1 | 1 | ✓ |
| Cl | 1 | 1 | ✓ |
All elements are balanced and the coefficients are the smallest whole numbers, so AgNO3 + NaCl = AgCl + NaNO3 is the correct balanced equation.
Molar masses and mole ratio
The balanced coefficients are also the mole ratio of the reaction. Using standard atomic masses, the molar mass of each substance is:
| Substance | Role | Molar mass (g/mol) | Moles |
|---|---|---|---|
| AgNO3 | reactant | 169.87 | 1 |
| NaCl | reactant | 58.44 | 1 |
| AgCl | product | 143.32 | 1 |
| NaNO3 | product | 84.99 | 1 |
For this reaction the mole ratio is 1 : 1 : 1 : 1. Combine these molar masses with the ratio in the free stoichiometry calculator to convert between moles, grams, and the number of particles for any reactant or product.
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