Cl₂ + 2NaBr → 2NaCl + Br₂

Chlorine and sodium bromide — balanced chemical equation, step by step.

Chlorine displaces bromine, demonstrating that halogens get less reactive down the group.

How to balance Cl2 + NaBr = NaCl + Br2

In a single-replacement reaction, one element displaces another from a compound. Balancing means choosing coefficients so that every element has the same number of atoms on both sides of the arrow — the Law of Conservation of Mass. Here is how it's done, step by step.

Step 1 — Write the unbalanced equation

Start with the correct formulas for every reactant and product:

Cl2 + NaBr = NaCl + Br2

Step 2 — Count the atoms of each element

With no coefficients yet (everything counted once), the atoms do not match. The ✗ marks show which elements are unbalanced:

Step 3 — Add the smallest whole-number coefficients

Adjust the coefficients in front of each formula until every element balances. The smallest whole-number coefficients are 1 Cl₂, 2 NaBr, 2 NaCl, 1 Br₂, giving:

Cl2 + 2NaBr = 2NaCl + Br2

For a single-replacement reaction, balance the element being displaced first, then balance the spectator ions, and finish with any free element or hydrogen gas.

Step 4 — Verify the balance

Recount every element. Each one now matches on both sides:

All elements are balanced and the coefficients are the smallest whole numbers, so Cl2 + 2NaBr = 2NaCl + Br2 is the correct balanced equation.

Molar masses and mole ratio

The balanced coefficients are also the mole ratio of the reaction. Using standard atomic masses, the molar mass of each substance is:

For this reaction the mole ratio is 1 : 2 : 2 : 1. Combine these molar masses with the ratio in the free stoichiometry calculator to convert between moles, grams, and the number of particles for any reactant or product.

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